document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2385>Question 2385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the distance between the points (3,17) and (-2,5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1011 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consider the line between the 2 points quoted to be the hypotenuse of a right-angled triangle. Use Pythagoras' theorem to find this distance.\r<BR>\n" );
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document.write( "The right angle of your triangle is at (3,5)...sketch it! YOU have to sketch things in maths!!!\r<BR>\n" );
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document.write( "horizontal line is length 3-(-2)=5<BR>\n" );
document.write( "vertical line is length 17-5 = 12\r<BR>\n" );
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document.write( "so, x^2 = 5^2 + 12^2<BR>\n" );
document.write( "--> x=13<BR>\n" );
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