document.write( "Question 138452: Find the center and radius by completing the square!
\n" ); document.write( "x^2+y^2-4ax-6ay+4a=0
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Algebra.Com's Answer #101099 by stanbon(75887)\"\" \"About 
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Find the center and radius by completing the square!
\n" ); document.write( "x^2+y^2-4ax-6ay+4a=0\r
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\n" ); document.write( "x^2 -4ax + (2a)^2 + y^2 - 6ay + (3a)2 = 4a^2 + 9a^2-4a
\n" ); document.write( "(x-2a)^2 + (y-3a)^2 = 13a^2-4a
\n" ); document.write( "Center: (2a , 3a)
\n" ); document.write( "Radius: sqrt(13a^2-4a)\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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