document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138401>Question 138401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The principal is $2,200. at 12% compounded semi-annually for 2 years. Determine the amount at the end of 2 years. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101074 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE FORMULA FOR THIS PROBLEM IS:<BR>\n" );
document.write( "P(1+R/N)^A*N WHERE P=PRINCIPLE, R=ANNUAL RATE, N=NUMBER OF INTEREST PERIOD & A=THE NUMBER OF YEARS.<BR>\n" );
document.write( "2,200(1+.12/2)^2*2<BR>\n" );
document.write( "2,200(1+.06)^4<BR>\n" );
document.write( "2,200(1.06)^4<BR>\n" );
document.write( "2,200*1.26<BR>\n" );
document.write( "$2,816 ANSWER FOR THE VALUE OF THE INVESTMENT AFTER 2 YEARS. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );