document.write( "Question 21042: The chemistry lab contains several solutions. Solution A is 80% acid while solution B is only 30% acid. How much of each solution is needed to make a 200L solution that is 62% acid \n" ); document.write( "
Algebra.Com's Answer #10106 by Paul(988)\"\" \"About 
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0.8x+0.3(200-x)=0.62(200)
\n" ); document.write( "0.8x+60-0.3x=120
\n" ); document.write( "0.5x=60
\n" ); document.write( "\"0.5x%2F0.5=60%2F0.5\"
\n" ); document.write( "x=120
\n" ); document.write( "200-120 = 80
\n" ); document.write( "Hence for 80% there is 120L solution needed and for 30% there is 80L of solution needed
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