document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138275>Question 138275</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0132203138/algebrahomeworkh>Blitzer College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> In a 1-mile race, the winner crosses the finish line 12 ft ahead of the second-place runner and 22 ft ahead of the third-place runner.  Assuming that each runner maintains a constant speed throughout the race, by how many feet does the second-place runner beat the third-place runner? (5280 ft in a mile) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101015 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101015\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a 1-mile race, the winner crosses the finish line 12 ft ahead of the second-place runner and 22 ft ahead of the third-place runner. Assuming that each runner maintains a constant speed throughout the race, by how many feet does the second-place runner beat the third-place runner? (5280 ft in a mile)<BR>\n" );
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document.write( "How far did the the 2nd and 3rd place runners travel when the winner crossed the the finish line (5280 ft)?<BR>\n" );
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document.write( "5280 - 12 = 5268 ft, traveled by the 2nd place runner<BR>\n" );
document.write( "5280 - 22 = 5258 ft, traveled by the 3rd place runner<BR>\n" );
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document.write( "Use a ratio equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5280%2F5268 ALIGN=MIDDLE  ALT=\"5280%2F5268\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F5258 ALIGN=MIDDLE  ALT=\"x%2F5258\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Cross multiply:<BR>\n" );
document.write( "5268x = 5280 * 5258<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=27762240%2F5268 ALIGN=MIDDLE  ALT=\"27762240%2F5268\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 5269.977 traveled by the 3rd place runner when the 2nd place runner crosses the finish line<BR>\n" );
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document.write( "5280 - 5269.977 = 10.023 ft is the distance the 2nd place runner beats the 3rd place runner<BR>\n" );
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document.write( "This makes sense because they were 10 ft apart when the winner crossed the line<BR>\n" );
document.write( "3rd place runner is a little over 10 ft behind the 2nd place guy, when he crosses the finish line because, he is slightly slower<BR>\n" );
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