document.write( "Question 137968: A researcher collected sample data for 11women ages 18 to 24 The sample had a mean serum cholesterol level (measured in mg/100 mL) of 189.9 with a standard deviation of 8.8. Assuming that serum cholesterol levels for women ages 18 to 24 are normally distributed, find a 95 confidence interval for the mean serum cholesterol level of all women in this age group. Then complete the table below.
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\n" ); document.write( "\n" ); document.write( "(If necessary, consult a list of formulas
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Algebra.Com's Answer #101003 by stanbon(75887)\"\" \"About 
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A researcher collected sample data for 11women ages 18 to 24 The sample had a mean serum cholesterol level (measured in mg/100 mL) of 189.9 with a standard deviation of 8.8. Assuming that serum cholesterol levels for women ages 18 to 24 are normally distributed, find a 95 confidence interval for the mean serum cholesterol level of all women in this age group.
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\n" ); document.write( "Formula:
\n" ); document.write( "x-bar = 189.9\r
\n" ); document.write( "\n" ); document.write( "E = t= 1.812 = 4.8078\r
\n" ); document.write( "\n" ); document.write( "95% CI: 189.9-4.8078 < u < 189.9+4.8078\r
\n" ); document.write( "\n" ); document.write( "95% CI: 185.09 < u < 194.71
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( "\n" ); document.write( " Then complete the table below.
\n" ); document.write( "Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. \r
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