document.write( "Question 138136: Daily output of Marathon's refinery is normally distributed with a mean of 232000 barrels of crude oil per day with a standard deviation of 7000 barrels.
\n" ); document.write( "What is the probability of producting at least 232000 barrels?
\n" ); document.write( "Between 232000 and 239000 barrels?
\n" ); document.write( "Less than 239000 barrels?
\n" ); document.write( "Less than 245000 barrels?
\n" ); document.write( "More than 225000 barrels?
\n" ); document.write( "

Algebra.Com's Answer #100982 by stanbon(75887)\"\" \"About 
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Daily output of Marathon's refinery is normally distributed with a mean of 232000 barrels of crude oil per day with a standard deviation of 7000 barrels.
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\n" ); document.write( "What is the probability of producting at least 232000 barrels?
\n" ); document.write( "P(0 < z) = 0.50
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\n" ); document.write( "Between 232000 and 239000 barrels?
\n" ); document.write( "P (232000 < x < 239000) = P(0 < z < [(239000-233200/7000]) = P(0\n" ); document.write( "---------------------------------
\n" ); document.write( "I have a feeling that you have posted the wrong standard deviation. Are you
\n" ); document.write( "sure it's not 70,000?
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "Less than 239000 barrels?
\n" ); document.write( "Less than 245000 barrels?
\n" ); document.write( "More than 225000 barrels?
\n" ); document.write( "
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