document.write( "Question 138210: Help, I can not figure out how to get the confidence interval for a t distribution. I really need step by step instructions.
\n" ); document.write( "For example if my sample mean is 2266.333, my standard deviation is 229.109, a random sample of 12 persons, find a 95% confidence interval for the mean number of miles driven. I can't figure this out, help
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Algebra.Com's Answer #100981 by stanbon(75887)\"\" \"About 
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For example if my sample mean is 2266.333, my standard deviation is 229.109, a random sample of 12 persons, find a 95% confidence interval for the mean number of miles driven.
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\n" ); document.write( "x-bar = 1166.333\r
\n" ); document.write( "\n" ); document.write( "E = t\r
\n" ); document.write( "\n" ); document.write( "t* for 95% confidence and df = 12-1 is 2.179\r
\n" ); document.write( "\n" ); document.write( "E = 2.179 = 144.115\r
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\n" ); document.write( "95% CI: 1166.333-144.115 < u < 1166.333+144.115\r
\n" ); document.write( "\n" ); document.write( "95% CI: 1022.218 < u < 1310.448
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\n" ); document.write( "Cheers,\r
\n" ); document.write( "\n" ); document.write( "Stan H.
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