document.write( "Question 138245:
\n" ); document.write( "6x^2-3x=-2 \n" ); document.write( "

Algebra.Com's Answer #100951 by checkley77(12844) $\"\"$ $\"About$

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6x^2-3x=-2
\n" ); document.write( "6x^2-3x+2=0
\n" ); document.write( "using the quadratic equation we get: $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "x=(3+-sqrt[-3^2-4*6*2])/2*6
\n" ); document.write( "x=(3+-sqrt[9-48])/12
\n" ); document.write( "x=(3+-sqrt-39)/12
\n" ); document.write( "x=(3+-6.245i)/12
\n" ); document.write( "x=3/12+-6.245i/12
\n" ); document.write( "x=.25+-.52i answers. \n" ); document.write( "

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