document.write( "Question 138232: How do you solve for each variable:
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document.write( "(x-3)(x-7)=0
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document.write( "b^2+3b-4=0
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document.write( "n^2+n-12=0
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document.write( "5x^2+18x=8
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document.write( "3a^2+4a=2a^2-2a-9 \n" );
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Algebra.Com's Answer #100941 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (x-3)(x-7)=0 \n" ); document.write( "the only way the product can be zero is if one of the factors is zero. \n" ); document.write( "x = 3 or x = 7 \n" ); document.write( "-------------------------- \n" ); document.write( "b^2+3b-4=0 \n" ); document.write( "(b+4)(b-1)=0 \n" ); document.write( "b = -4 or b = 1 \n" ); document.write( "------------------- \n" ); document.write( "n^2+n-12=0 \n" ); document.write( "(n+4)(n-3)=0 \n" ); document.write( "n=-4 or n=3 \n" ); document.write( "-------------------- \n" ); document.write( "5x^2+18x=8 \n" ); document.write( "5x^2+18x-8 = 0 \n" ); document.write( "(5x-2)(x+4) = 0 \n" ); document.write( "x = 2/5 or x = -4 \n" ); document.write( "----------------------- \n" ); document.write( "3a^2+4a=2a^2-2a-9 \n" ); document.write( "a^2+6a+9 = 0 \n" ); document.write( "(a+3)(a+3) = 0 \n" ); document.write( "a=-3 with multiplicity two \n" ); document.write( "---------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |