document.write( "Question 138232: How do you solve for each variable:
\n" ); document.write( "(x-3)(x-7)=0
\n" ); document.write( "b^2+3b-4=0
\n" ); document.write( "n^2+n-12=0
\n" ); document.write( "5x^2+18x=8
\n" ); document.write( "3a^2+4a=2a^2-2a-9
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Algebra.Com's Answer #100941 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(x-3)(x-7)=0
\n" ); document.write( "the only way the product can be zero is if one of the factors is zero.
\n" ); document.write( "x = 3 or x = 7
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\n" ); document.write( "b^2+3b-4=0
\n" ); document.write( "(b+4)(b-1)=0
\n" ); document.write( "b = -4 or b = 1
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\n" ); document.write( "n^2+n-12=0
\n" ); document.write( "(n+4)(n-3)=0
\n" ); document.write( "n=-4 or n=3
\n" ); document.write( "--------------------
\n" ); document.write( "5x^2+18x=8
\n" ); document.write( "5x^2+18x-8 = 0
\n" ); document.write( "(5x-2)(x+4) = 0
\n" ); document.write( "x = 2/5 or x = -4
\n" ); document.write( "-----------------------
\n" ); document.write( "3a^2+4a=2a^2-2a-9
\n" ); document.write( "a^2+6a+9 = 0
\n" ); document.write( "(a+3)(a+3) = 0
\n" ); document.write( "a=-3 with multiplicity two
\n" ); document.write( "----------------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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