document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138243>Question 138243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me to solve the equation:\r<BR>\n" );
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document.write( "16/x^2=8/x+6\r<BR>\n" );
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document.write( "I know the LCD is x^2(x+6) and I multiply each term and I get\r<BR>\n" );
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document.write( "16(x+6)=8x^2\r<BR>\n" );
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document.write( "which turns into the equation\r<BR>\n" );
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document.write( "8x^2-16x+96=0 (right?)\r<BR>\n" );
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document.write( "which is where I get confused. I'm not sure if I am suposed to factor it out or use the quadratic formula to solve it. I know though that the answer involves a square root.\r<BR>\n" );
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document.write( "Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #100940 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=100940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the 96 should be negative __ dividing by 8 __ x^2-2x-12=0\r<BR>\n" );
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document.write( "not factorable, so use quadratic formula __ x=[2 +- sqrt(4+48)]/2 __ x=1 +- sqrt(13) </SPAN>\n" );
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