document.write( "Question 18522: Prove the following identity: tan^2x - sin^2x = (sin^2x)(tan^2x) \n" ); document.write( "
Algebra.Com's Answer #10094 by kapilsinghi(68)\"\" \"About 
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tan^2x - sin^2x = (sin^2x)(tan^2x)\r
\n" ); document.write( "\n" ); document.write( "sin^2x/cos^2x - sin^2x
\n" ); document.write( "sin^2x(1/cos^2x - 1)
\n" ); document.write( "sin^2x((1-cos^2x)/cos^2x)
\n" ); document.write( "sin^2x(sin^2x/cos^2x)
\n" ); document.write( "sin^2x(tan^2x) \r
\n" ); document.write( "\n" ); document.write( "kapilsinghi123@gmail.com
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