document.write( "Question 138228: Given -x^2-6x-3, is the vertex a maximum or minimum for the function? What is the value fo that maximum or minimum?\r
\n" ); document.write( "\n" ); document.write( "There is nothing in my book about maximums and minimums, please help!
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Algebra.Com's Answer #100934 by solver91311(24713)\"\" \"About 
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Algebra solution:\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=ax%5E2%2Bbx%2Bc\" is a parabola that opens upward when \"a%3E0\" or downward when \"a%3C0\" (and is no longer a parabola if \"a=0\"). Your value for a is -1, so the parabola opens downward and the vertex is then a maximum.\r
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\n" ); document.write( "\n" ); document.write( "The x-coordinate of the vertex is given by \"%28-b%29%2F2a\", so for your function:
\n" ); document.write( "\"%28-%28-6%29%29%2F2%28-1%29=3\". The value of the function at that point is \"f%283%29=-%283%29%5E2-6%283%29-3=-9-18-3=-30\".\r
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\n" ); document.write( "\n" ); document.write( "Calculus solution:
\n" ); document.write( "A continuous function has a local extrema wherever the first derivitive is equal to zero. It is a maximum if the 2nd derivitive is negative at that point and a minimum if the 2nd derivitive is positive at that point.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=y=-x%5E2-6x-3\" => \"dy%2Fdx=-2x-6\"\r
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\n" ); document.write( "\n" ); document.write( "Let \"-2x-6=0\" => local extrema at \"x=3\", and the value of the function at that point is found the same way as in the algebra solution: \"f%283%29=-%283%29%5E2-6%283%29-3=-9-18-3=-30\".\r
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\n" ); document.write( "\n" ); document.write( "\"d%5E2y%2Fdx%5E2=-2\" => the 2nd derivitive is everywhere negative, so the local extreme point is a maximum.
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