document.write( "Question 138214: How do you draw a figure with an area of 64 cm squared and a perimeter of 64 cm????? I have tried trial and error, but it does not seem to be working. Please help me. Thank you. \n" ); document.write( "
Algebra.Com's Answer #100933 by ankor@dixie-net.com(22740)\"\" \"About 
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How do you draw a figure with an area of 64 cm squared and a perimeter of 64 cm
\n" ); document.write( "Trial and error will be difficult because I don't think the sides will be integers.
\n" ); document.write( ":
\n" ); document.write( "Let x = length
\n" ); document.write( "Let y = width
\n" ); document.write( ":
\n" ); document.write( "x*y = 64; area equation
\n" ); document.write( "and
\n" ); document.write( "2x + 2y = 64; perimeter equation
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "x + y = 32
\n" ); document.write( "y = (32-x)
\n" ); document.write( ":
\n" ); document.write( "Substitute (32-x) for y in the area equation
\n" ); document.write( "x(32-x) = 64
\n" ); document.write( "32x - x^2 - 64 = 0
\n" ); document.write( "Multiply equation by -1, arrange as a quadratic equation:
\n" ); document.write( "x^2 - 32x + 64 = 0
\n" ); document.write( ":
\n" ); document.write( "Use the quadratic formula; a=1; b=-32; c=64
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%28-%28-32%29+%2B-+sqrt%28-32%5E2+-+4+%2A+1+%2A+64+%29%29%2F%282%2A1%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%2832+%2B-+sqrt%281024+-+256+%29%29%2F%282%29+\"\r
\n" ); document.write( "\n" ); document.write( "If you do the math here you will get two solutions
\n" ); document.write( ":
\n" ); document.write( "x = 29.8564 or x = 2.1436 One value is the length and the other is the width
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