document.write( "Question 138195: I also have to set up a three equation problem as well but once again I don't understand it.\r
\n" ); document.write( "\n" ); document.write( "If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid number plus 2 times the first number is 3. The first number plus 3 times the second number plus the third number is 18. Find the three numbers. \r
\n" ); document.write( "\n" ); document.write( "Thank you for your help. \n" ); document.write( "

Algebra.Com's Answer #100909 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "First number:  x
\n" );
document.write( "Second number: y
\n" );
document.write( "Third number:  z\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "The sum of the 1st number and 2 times the third: x + 2z
\n" );
document.write( "Then subtract the 2nd number x + 2z - y, or x - y + 2z to keep things in order.
\n" );
document.write( "The result is 1:  x - y + 2z = 1\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "2 times the 1st number: 2x
\n" );
document.write( "Plus the 3rd number:    2x + z
\n" );
document.write( "'is' means equals, so   2x + z = 3\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "The 1st number, x, plus 3 times the 2nd, 3y, plus the 3rd, z 
\n" );
document.write( "is (=) 18, so:
\n" );
document.write( "x + 3y + z = 18\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "So, here are your three equations.
\n" );
document.write( " x -  y + 2z = 1
\n" );
document.write( "2x      +  z = 3
\n" );
document.write( " x + 3y +  z = 18\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "Looking at the coefficients, I would say that Gauss-Jordan elimination is the
\n" );
document.write( "best solution method.  But you do it however you like. \n" );
document.write( "

\n" );