document.write( "Question 138195: I also have to set up a three equation problem as well but once again I don't understand it.\r
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document.write( "If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid number plus 2 times the first number is 3. The first number plus 3 times the second number plus the third number is 18. Find the three numbers. \r
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document.write( "Thank you for your help. \n" );
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Algebra.Com's Answer #100908 by stanbon(75887) ![]() You can put this solution on YOUR website! If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. \n" ); document.write( "a+2c-b = 1 \n" ); document.write( "----------------- \n" ); document.write( "The third number plus 2 times the first number is 3. \n" ); document.write( "c +2a = 3 \n" ); document.write( "--------------------- \n" ); document.write( "The first number plus 3 times the second number plus the third number is 18. \n" ); document.write( "a+3b+c = 18 \n" ); document.write( "------------------------------ \n" ); document.write( "Find the three numbers. \n" ); document.write( "--------------------------------- \n" ); document.write( "Rearrange the equations: \n" ); document.write( "a - b + 2c = 1 \n" ); document.write( "2a + 0 + c = 3 \n" ); document.write( "a + 3b + c = 18 \n" ); document.write( "------------------------- \n" ); document.write( "Using Matrix methods I get: \n" ); document.write( "a= 0 \n" ); document.write( "b= 5 \n" ); document.write( "c= 3 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |