document.write( "Question 138181: The lenght of an altitude of a triangle is one-third the lenght of the side to which it is drawn. If the area of the triangle is 6 square centimeters, find the lenght of that attitude? \n" ); document.write( "
Algebra.Com's Answer #100907 by solver91311(24713)\"\" \"About 
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The area of a triangle is \"A=%281%2F2%29bh\" where b is the base and h is the height or altitude. The base is that side of the triangle to which the altitude is drawn.\r
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\n" ); document.write( "\n" ); document.write( "So, if x is the altitude then 3x is the base because the length of the altitute is one third the length of the base.\r
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\n" ); document.write( "\n" ); document.write( "Substituting in the area formula: \"%281%2F2%29%283x%29%28x%29=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%293x%5E2=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29x%5E2=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%284%29=2\" (ignore the negative square root because we are calculating a length)\r
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\n" ); document.write( "\n" ); document.write( "So, the altitude is \"2\".\r
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\n" ); document.write( "\n" ); document.write( "Check the answer:\r
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\n" ); document.write( "\n" ); document.write( "\"A=%281%2F2%29bh\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=3h=3%2A2=6\", so\r
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\n" ); document.write( "\n" ); document.write( "\"A=%281%2F2%29%286%29%282%29=6\" Answer checks.
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