document.write( "Question 137873: can you please factor this problem for me and show how it is done:\r
\n" ); document.write( "\n" ); document.write( "x squared + 6x - 72
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Algebra.Com's Answer #100777 by Fombitz(32388)\"\" \"About 
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\"x%5E2%2B6x-72=%28x%2Ba%29%28x%2Bb%29\"
\n" ); document.write( "a and b are constants that solve these equations.
\n" ); document.write( "\"ab=-72\"
\n" ); document.write( "\"a%2Bb=6\"
\n" ); document.write( "First, look at factors of 72.
\n" ); document.write( "1,72
\n" ); document.write( "2,36
\n" ); document.write( "3,24
\n" ); document.write( "4,18
\n" ); document.write( "6,12
\n" ); document.write( "8,9
\n" ); document.write( "Then look for combinations of the factors where the sum or difference might be 6.
\n" ); document.write( "6 and 12 look like a good bet.
\n" ); document.write( "Now we can match the sign (positive or negative) of each factor to solve the two equations.
\n" ); document.write( "Since the product is -72, one of the factors is negative.
\n" ); document.write( "Since the sum is positive, the smaller number (6) must be negative.
\n" ); document.write( "a=12 and b=-6 meets all of our criteria.
\n" ); document.write( "\"x%5E2%2B6x-72=%28x%2Ba%29%28x%2Bb%29\"
\n" ); document.write( "\"x%5E2%2B6x-72=%28x%2B12%29%28x-6%29\"
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