document.write( "Question 137774: Okay, I have another one using distance = rate times time but it has a twist. I am totally stuck! Please help!
\n" ); document.write( "A penguin swimming with the ocean current in search of food takes 1 hour to travel 9 miles. Its return trip upstream to its starting point takes it 3 hours. What is the penguin's speed in still water?
\n" ); document.write( "I figured its speed with the current and against it but have no idea how to figure out still water. HELP!
\n" ); document.write( "with current- 9=1r so r=9
\n" ); document.write( "against current- 9=3r so r=3
\n" ); document.write( "Now what???
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Algebra.Com's Answer #100750 by Fombitz(32388)\"\" \"About 
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No, you need to figure in the ocean current in the rate.
\n" ); document.write( "Let's call the it R.
\n" ); document.write( "If the penguin floats (doesn't swim), then he would travel at rate, R.
\n" ); document.write( "When he's with the current, his rate is P+R, where P is his speed in still water.
\n" ); document.write( "When he's against the current, his rate is P-R.
\n" ); document.write( "Remember rate times time equals distance.
\n" ); document.write( "The distance is 9 miles.
\n" ); document.write( "Time with current is 1 hours.
\n" ); document.write( "Time against current is 3 hours.
\n" ); document.write( "1.\"%28P%2BR%29%281%29=9\"
\n" ); document.write( "2.\"%28P-R%29%283%29=9\"
\n" ); document.write( "Simplifying
\n" ); document.write( "1.\"P%2BR=9\"
\n" ); document.write( "2.\"P-R=3\"
\n" ); document.write( "The simplest way is to add the two together to cancel out R.
\n" ); document.write( "\"2P=12\"
\n" ); document.write( "\"P=6\"
\n" ); document.write( "From 1,
\n" ); document.write( "\"P%2BR=9\"
\n" ); document.write( "\"6%2BR=9\"
\n" ); document.write( "\"R=3\"
\n" ); document.write( "The ocean current, R, is 3 miles per hour.
\n" ); document.write( "The penguin speed, P, in still water is 6 miles per hour. \r
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