document.write( "Question 137736: 1-4w^2=w^2+11 \n" ); document.write( "

Algebra.Com's Answer #100741 by checkley77(12844) $\"\"$ $\"About$

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1-4w^2=w^2+11
\n" ); document.write( "-4w^2-w^2=1+11
\n" ); document.write( "-5w^2=12
\n" ); document.write( "w^2=12/-5
\n" ); document.write( "w^2=-12/5
\n" ); document.write( "w=sqrt(-12/5
\n" ); document.write( "w=2sqrt(-3/5) answer.\r
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