document.write( "Question 137749: find four consecutive odd integers such that the sum of the first and fourth is 55 greater than the opposite of the third \n" ); document.write( "
Algebra.Com's Answer #100720 by solver91311(24713)\"\" \"About 
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First odd integer: x
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\n" ); document.write( "3rd odd integer: x + 4
\n" ); document.write( "4th odd integer: x + 6\r
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\n" ); document.write( "\n" ); document.write( "Sum of the 1st and the 4th: x + (x + 6) = 2x + 6\r
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\n" ); document.write( "\n" ); document.write( "Opposite of the 3rd: -(x + 4)\r
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\n" ); document.write( "\n" ); document.write( "The sum of the 1st and 4th (2x + 6) is (=) 55 greater than (+55) the opposite of the 3rd (-(x+4)), so: \"2x%2B6=-%28x%2B4%29%2B55\"\r
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\n" ); document.write( "\n" ); document.write( "Solve that equation for x to give you the first one, and the others follow.
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