document.write( "Question 137729: Can someone tell me if I am doing this right? The problem is...1/2|x-2|<4
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document.write( "If I pull the x-2 out of the absolute value, it becomes x+2 so I now have 1/2(x+2)<4. Multiply it out...x + 2/2 < 4. Divide 4 by 2...x + 2/2 < 4/2 So, the answer I get is x < 2.\r
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document.write( "It seems too easy. Thanks :) \n" );
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Algebra.Com's Answer #100709 by stanbon(75887) ![]() You can put this solution on YOUR website! 1/2|x-2|<4\r \n" ); document.write( "\n" ); document.write( "Multiply both sides by 2 to get: \n" ); document.write( "|x-2| < 4 \n" ); document.write( "That means: \n" ); document.write( "-4 < x-2 < 4 \n" ); document.write( "Add 2 along the line to get: \n" ); document.write( "-2 < x < 6 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |