document.write( "Question 137676: John and Mike have been friends since school but havent seen eachother in many years, so they agree to meet on saturday. John leaves his house at 10:00 am and drives east at 50 miles per hour. Mike leaves his house at the same time and drives west at 45 miles per hour. if their houses are connected by a straight highway running east-west (no stoplight or towns in the way) and are 350 miles apart. How far from johns house will they meet?. at what time will they meet? \n" ); document.write( "
Algebra.Com's Answer #100695 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let t=time that elapses before they meet
\n" ); document.write( "Distance John travels=d
\n" ); document.write( "Distance Mike travels=(360-d)
\n" ); document.write( "John's time=d/50
\n" ); document.write( "Mikes's time=(360-d)/45\r
\n" ); document.write( "\n" ); document.write( "Now we know that John's time has to equal Mike's time, so:\r
\n" ); document.write( "\n" ); document.write( "d/50=(360-d)/45 multiply each side by 50*45 (or cross multiply)\r
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\n" ); document.write( "\n" ); document.write( "45d=50(360-d) or
\n" ); document.write( "45d=18000-50d add 50 d to both sides
\n" ); document.write( "45d+50d=18000
\n" ); document.write( "95d=18000 divide both sides by 95
\n" ); document.write( "d=~189.5 mi------------------------------distance John travels (also distance from John's house)
\n" ); document.write( "360-d=360-189.5=~170.5 mi---------------------distance Mike travels\r
\n" ); document.write( "\n" ); document.write( "John's time: t=d/r=189.5/50=3.79 hr-------------3h 47.4m
\n" ); document.write( "Mike's time: t=d/r=170.5/45=3.79 hr--------------3h 47.4m\r
\n" ); document.write( "\n" ); document.write( "Time when they meet=10:00AM + 3h 47.4m=1:47.4pm. \r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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