document.write( "Question 137656: Solve by the elimination method.
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document.write( "0.05x+0.25y=11
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document.write( "0.15x+0.05=12
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document.write( "What is the solution of the system?
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document.write( "Again can someone explain how I am supposed to do this? I do not seem to understand anything that anyone has said. I am getting soooooo aggrevated. \n" );
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Algebra.Com's Answer #100686 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve by the elimination method. \n" ); document.write( "0.05x+0.25y=11 \n" ); document.write( "0.15x+0.05y=12 \n" ); document.write( "What is the solution of the system? \n" ); document.write( ": \n" ); document.write( "Let's get rid of the decimals, multiply both equations by 100 \n" ); document.write( " 5x + 25y = 1100 \n" ); document.write( "15x + 5y = 1200 \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by -3 and add to the 2nd equation \n" ); document.write( "-15x - 75y = -3300 \n" ); document.write( "+15x + 5y = 1200 \n" ); document.write( "---------------------addition eliminates x; find y \n" ); document.write( "0x - 70x = -2100 \n" ); document.write( "x = \n" ); document.write( "x = +30 \n" ); document.write( ": \n" ); document.write( "Find y using the equation; 5x + 25y = 1100, substitute 30 for x: \n" ); document.write( "5(30) + 25y = 1100 \n" ); document.write( "150 + 25y = 1100 \n" ); document.write( "25y = 1100 - 150 \n" ); document.write( "25y = 950 \n" ); document.write( "y = \n" ); document.write( "y = 38 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the 1st original equation, substitute for x and y: \n" ); document.write( ".05(30) + .25(38) = \n" ); document.write( " 1.5 + 9.5 = 11; confirms out solutions \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Was I able to make this understandable to you? Any questions? \n" ); document.write( " |