document.write( "Question 137656: Solve by the elimination method.
\n" ); document.write( "0.05x+0.25y=11
\n" ); document.write( "0.15x+0.05=12
\n" ); document.write( "What is the solution of the system?
\n" ); document.write( "Again can someone explain how I am supposed to do this? I do not seem to understand anything that anyone has said. I am getting soooooo aggrevated.
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Algebra.Com's Answer #100686 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Solve by the elimination method.
\n" ); document.write( "0.05x+0.25y=11
\n" ); document.write( "0.15x+0.05y=12
\n" ); document.write( "What is the solution of the system?
\n" ); document.write( ":
\n" ); document.write( "Let's get rid of the decimals, multiply both equations by 100
\n" ); document.write( " 5x + 25y = 1100
\n" ); document.write( "15x + 5y = 1200
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by -3 and add to the 2nd equation
\n" ); document.write( "-15x - 75y = -3300
\n" ); document.write( "+15x + 5y = 1200
\n" ); document.write( "---------------------addition eliminates x; find y
\n" ); document.write( "0x - 70x = -2100
\n" ); document.write( "x = \"%28-2100%29%2F%28-70%29\"
\n" ); document.write( "x = +30
\n" ); document.write( ":
\n" ); document.write( "Find y using the equation; 5x + 25y = 1100, substitute 30 for x:
\n" ); document.write( "5(30) + 25y = 1100
\n" ); document.write( "150 + 25y = 1100
\n" ); document.write( "25y = 1100 - 150
\n" ); document.write( "25y = 950
\n" ); document.write( "y = \"950%2F25\"
\n" ); document.write( "y = 38
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the 1st original equation, substitute for x and y:
\n" ); document.write( ".05(30) + .25(38) =
\n" ); document.write( " 1.5 + 9.5 = 11; confirms out solutions
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Was I able to make this understandable to you? Any questions?
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