document.write( "Question 137571: hannah took a trip to visit her cousin.she drove 120 miles to reach her cousin's house and the same distance back home.
\n" ); document.write( "it took her 1.2 hours to get halfway to her cousin's house. what was her average speed,in miles per hour, for the first 1.2 hours of the trip?\r
\n" ); document.write( "\n" ); document.write( "hanna's average speed for the remainder of the trip to her cousin's house was 40 per hour . how long, in hours, did it take her to drive the remaining distance?\r
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\n" ); document.write( "\n" ); document.write( "traveling home along the same route, hanna drove at an average rate of 55 miles per hour.after 2 hour her car broke down. how many miles was she from home?
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Algebra.Com's Answer #100644 by ankor@dixie-net.com(22740)\"\" \"About 
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hannah took a trip to visit her cousin.she drove 120 miles to reach her cousin's house and the same distance back home.
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\n" ); document.write( "it took her 1.2 hours to get halfway to her cousin's house. what was her average speed,in miles per hour, for the first 1.2 hours of the trip?
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\n" ); document.write( "Half of 120 mi is 60 mi
\n" ); document.write( "60 mi in 1.2 hrs (Speed = dist/time)
\n" ); document.write( "Av speed = \"60%2F1.2\" = 50 mph
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\n" ); document.write( "hanna's average speed for the remainder of the trip to her cousin's house was 40 per hour . how long, in hours, did it take her to drive the remaining distance?
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\n" ); document.write( "Remainder is also 60 mi: (Time = dist/speed)
\n" ); document.write( "Time = \"60%2F40\" = 1.5 hrs
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\n" ); document.write( ":
\n" ); document.write( "traveling home along the same route, hanna drove at an average rate of 55 miles per hour.after 2 hour her car broke down. how many miles was she from home?
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\n" ); document.write( "Find the distance covered in 2 hr, at 55 mph. (Dist = speed * time)
\n" ); document.write( "Dist = 55 * 2 = 110 miles
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\n" ); document.write( "Distance from home: 120 - 110 = 10 mi
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