document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=137500>Question 137500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by the substitution method.\r<BR>\n" );
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document.write( "4x+7y = 35\r<BR>\n" );
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document.write( "-3x+y = 30<BR>\n" );
document.write( "Can someone please help me with this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #100597 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=100597\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x+7y = 35 <BR>\n" );
document.write( "-3x+y = 30\r<BR>\n" );
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document.write( "y=3x+30 (from 2nd eq)<BR>\n" );
document.write( "then<BR>\n" );
document.write( "using it at 1st eq we have<BR>\n" );
document.write( "4x+7(3x+30)=35<BR>\n" );
document.write( "25x+210=35<BR>\n" );
document.write( "25x=-175<BR>\n" );
document.write( "x=-7<BR>\n" );
document.write( "y=3(-7)+30=9<BR>\n" );
document.write( "Answer: x=-7,y=9 </SPAN>\n" );
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