document.write( "Question 137421: solve the following by factoring:\r
\n" ); document.write( "\n" ); document.write( "5t squared - 10t = 0\r
\n" ); document.write( "\n" ); document.write( "x squared - 3x - 10 = 0\r
\n" ); document.write( "\n" ); document.write( "if f(x) = 3x squared + 5x -2 find\r
\n" ); document.write( "\n" ); document.write( "f(-2)\r
\n" ); document.write( "\n" ); document.write( "f(4)\r
\n" ); document.write( "\n" ); document.write( "solve \r
\n" ); document.write( "\n" ); document.write( "3x squared + 19x - 14 = 0 using quadratic formula.
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Algebra.Com's Answer #100545 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve by factoring:
\n" ); document.write( "1)
\n" ); document.write( "\"5t%5E2-10t+=+0\" Factor out 5t from each term:
\n" ); document.write( "\"5t%28t-2%29+=+0\" Now apply the zero products rule;
\n" ); document.write( "\"5t+=+0\" and/or \"t-2+=+0\"
\n" ); document.write( "If \"5t+=+0\" then \"t+=+0\"
\n" ); document.write( "If \"t-2+=+0\" then \"t+=+2\"
\n" ); document.write( "2)
\n" ); document.write( "\"x%5E2-3x-10+=+0\" Factor the trinomial.
\n" ); document.write( "\"%28x%2B2%29%28x-5%29+=+0\" Apply the zero products rule.
\n" ); document.write( "\"x%2B2+=+0\" and/or \"x-5+=+0\"
\n" ); document.write( "If \"x%2B2+=+0\" then \"x+=+-2\"
\n" ); document.write( "If \"x-5+=+0\" then \"x+=+5\"
\n" ); document.write( "3)
\n" ); document.write( "\"f%28x%29+=+3x%5E2%2B5x-2\" find: f(-2). Just substitute -2 everywhere there is an x in the function.
\n" ); document.write( "\"f%28-2%29+=+3%28-2%29%5E2%2B5%28-2%29-2\" Simplify.
\n" ); document.write( "\"f%28-2%29+=+3%284%29%2B%28-10%29-2\"
\n" ); document.write( "\"f%28-2%29+=+12-10-2\"
\n" ); document.write( "\"f%28-2%29+=+0\"
\n" ); document.write( "Find: f(4)
\n" ); document.write( "\"f%284%29+=+3%284%29%5E2%2B5%284%29-2\"
\n" ); document.write( "\"f%284%29+=+3%2816%29%2B20-2\"
\n" ); document.write( "\"f%284%29+=+48%2B20-2\"
\n" ); document.write( "\"f%284%29+=+66\"
\n" ); document.write( "4) Solve for x using the quadratic formula:\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"
\n" ); document.write( "\"3x%5E2%2B19x-14+=+0\" Here, a = 3, b = 19, and c = -14. Making the appropriate substitutions, we get:
\n" ); document.write( "\"x+=+%28-19%2B-sqrt%28%2819%29%5E2-4%283%29%28-14%29%29%29%2F2%283%29\" Simplify this:
\n" ); document.write( "\"x+=+%28-19%2B-sqrt%28361-%28-168%29%29%29%2F6\"
\n" ); document.write( "\"x+=+%28-19%2B-sqrt%28529%29%29%2F6\"
\n" ); document.write( "\"x+=+%28-19%2B23%29%2F6\" or \"x+=+%28-19-23%29%2F6\"
\n" ); document.write( "\"x+=+2%2F3\" or \"x+=+-7\"
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