document.write( "Question 137403This question is from textbook
\n" ); document.write( ": Tutor please help and would you please solve by substitution method.\r
\n" ); document.write( "\n" ); document.write( "x = 1/8y - 1\r
\n" ); document.write( "\n" ); document.write( "y = 1/4x + 39\r
\n" ); document.write( "\n" ); document.write( "I would be very grateful for your help.
\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #100536 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
solve by substitution method.
\n" ); document.write( "x = 1/8y - 1
\n" ); document.write( "y = 1/4x + 39
\n" ); document.write( "-------------------
\n" ); document.write( "y = (1/4)[(1/8)y - 1] + 39\r
\n" ); document.write( "\n" ); document.write( "y = (1/32)y - (1/4) + 39\r
\n" ); document.write( "\n" ); document.write( "(31/32)y = (155/4)\r
\n" ); document.write( "\n" ); document.write( "(31/8)y = 155
\n" ); document.write( "(1/8)y = 31
\n" ); document.write( "y = 248
\n" ); document.write( "--------------
\n" ); document.write( "Substitute into x = (1/8)y -1 to solve for \"x\"
\n" ); document.write( "x = (1/8)248 -1
\n" ); document.write( "x = 32
\n" ); document.write( "===================
\n" ); document.write( "Final Answer: x = 32, y = 248
\n" ); document.write( "=====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

\n" );