document.write( "Question 137387: How would i solve these two word problems??? \r
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\n" ); document.write( "\n" ); document.write( "1)An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.\r
\n" ); document.write( "\n" ); document.write( "2)Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
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Algebra.Com's Answer #100530 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2)An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away.
\n" ); document.write( "The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.
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\n" ); document.write( "Express DATA:
\n" ); document.write( "Distance = 50 miles : Rate = 2x mph ; time = 50/2x
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\n" ); document.write( "Local train DATA:
\n" ); document.write( "Distance = 50 miles ; Rate = x mph ; time = 50/x
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\n" ); document.write( "EQUATION:
\n" ); document.write( "local train time - express train time = 1 hr
\n" ); document.write( "50/x - 50/2x = 1
\n" ); document.write( "Multiply thru by 2x to get:
\n" ); document.write( "100 - 50 = 2x
\n" ); document.write( "50 = 2x
\n" ); document.write( "x = 25 mph ( speed of the local train)
\n" ); document.write( "2x = 50 mph ( speed of the express)
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\n" ); document.write( "Joe has a collection of nickels and dimes that is worth $5.65.
\n" ); document.write( "If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45.
\n" ); document.write( "How many dimes does he have?
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\n" ); document.write( "EQUATIONS:
\n" ); document.write( "5n + 10d = 565 cents
\n" ); document.write( "5(n+8) + 10(2d) = 1045
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\n" ); document.write( "5n + 10d = 565
\n" ); document.write( "5n + 20d = 1005
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\n" ); document.write( "Subtract 1st from 2nd to get:
\n" ); document.write( "10d = 440
\n" ); document.write( "d = 44 (# of dimes)
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\n" ); document.write( "Substitute into 5n+10d=565 to solve for \"n\"
\n" ); document.write( "5n+10*44 = 565
\n" ); document.write( "5n + 440 = 565
\n" ); document.write( "5n = 125
\n" ); document.write( "n = 25 (# of nickels)
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.\r
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