document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=137379>Question 137379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> my problem is this, A fossilized leaf contains6% of its normal amount of carbon 14. how old is the fossil (to the nearest year)? use 5600 years as the half-life of carbon 14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #100527 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=100527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=I(1/2)^(t/h) __ where a=current amount, I=initial amount, t=time elapsed, and h=half-life\r<BR>\n" );
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document.write( ".06I=I(1/2)^(t/5600) __ dividing by I __ .06=(1/2)^(t/5600)\r<BR>\n" );
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document.write( "taking log __ log(.06)=(log(1/2))(t/5600)\r<BR>\n" );
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document.write( "dividing by log(1/2) __ (log(.06))/(log(1/2))=(t/5600)\r<BR>\n" );
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document.write( "multiplying by 5600 __ 5600[(log(.06))/(log(1/2))]=t </SPAN>\n" );
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