document.write( "Question 137356: I am finding partial decomposition very intimidating-Please help if you can:)Thank You very much!
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document.write( "Find the unknowns on the right side of the partial fraction decomposition.
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document.write( "x+3/x^3+64=A/x=4+Bx+C/x^2-4x+16 \n" );
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Algebra.Com's Answer #100500 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the unknowns on the right side of the partial fraction decomposition. \n" ); document.write( "(x+3)/(x^3+64) = (x+3)/[(x+4)(x^2-4x+16)\r \n" ); document.write( "\n" ); document.write( "(x+3)/(x^3+64) = A/(x+4) + (Bx+C)/(x^2-4x+16) \n" ); document.write( "The denominators are the same so just work with the numerators:\r \n" ); document.write( "\n" ); document.write( "x+3 = A(x^2-4x+16) + (Bx+C)(x+4)\r \n" ); document.write( "\n" ); document.write( "x+3 = Ax^2-4Ax+16A + Bx^2+4Bx + Cx + 4C \r \n" ); document.write( "\n" ); document.write( "x+3 = (A+B)x^2 + (4B-4A+C)x + (16A +4C) \n" ); document.write( "---------------- \n" ); document.write( "EQUATIONS: \n" ); document.write( " A + B + 0 = 0 \n" ); document.write( "-4A +4B + C = 1 \n" ); document.write( "16A +0 +4C = 3 \n" ); document.write( "-------------------- \n" ); document.write( "Solving for A, B, and C you get:\r \n" ); document.write( "\n" ); document.write( "A = -1/48 \n" ); document.write( "B = 1/48 \n" ); document.write( "C = 40/48 \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |