document.write( "Question 137337: Solve the problem. Solve the equation 12x to third power - 77x to second power + 91x - 30 = 0 given that 2/3 is a root. \n" ); document.write( "

Algebra.Com's Answer #100469 by Edwin McCravy(20056) $\"\"$ $\"About$

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Solve the problem. Solve the equation 12x to third power - 77x to second power + 91x - 30 = 0 given that 2/3 is a root.
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document.write( " given that  is a root.\r\n" );
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document.write( "Since  is a root, then the polynomial is divisible by \r\n" );
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document.write( "So we can divide that synthetically this way:\r\n" );
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document.write( " | 12 -77  91 -30\r\n" );
document.write( "   |      8 -46  30 \r\n" );
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document.write( "     12 -69  45   0\r\n" );
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document.write( "So we have factored the polynomial this way\r\n" );
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document.write( "Now we can factor a 3 out of the second parentheses, getting:\r\n" );
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document.write( "Factor the trinomial in the second parentheses\r\n" );
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document.write( "If you like you can move the  factor in front of\r\n" );
document.write( "the first factor:\r\n" );
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document.write( "and distribute the 3 into the \r\n" );
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document.write( "That's the complete factorization of the\r\n" );
document.write( "original polynomial. Now we use the zero-factor\r\n" );
document.write( "principle and set each factor equal to 0\r\n" );
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document.write( " gives solution  which we knew from the start.\r\n" );
document.write( " gives solution \r\n" );
document.write( " gives solution \r\n" );
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document.write( "Edwin

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