document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20890>Question 20890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line that passes through the point (2;1) and is parallel to the line y = 3/4 x + 7. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10044 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> well since parallel lines have the same slope we know that the new line has a slope of 3/4 so now we can either solve the equation  y=mx+b for b and then plug in or use the point slope formula.\r<BR>\n" );
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document.write( "solving for b we get\r<BR>\n" );
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document.write( "y=mx+b where m=3/4 x=2 and y=1\r<BR>\n" );
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document.write( "1=3/4(2)+b<BR>\n" );
document.write( "1 = 3/2+b<BR>\n" );
document.write( "-1/2 = b\r<BR>\n" );
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document.write( "y=3/4x-1/2\r<BR>\n" );
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document.write( "using point-slope form you get\r<BR>\n" );
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document.write( "y-y1=m(x-x1) where m=3/4 y1=1 and x1=2\r<BR>\n" );
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document.write( "y-1=3/4(x-2)<BR>\n" );
document.write( "y=3/4x-3/2+1<BR>\n" );
document.write( "y=3/4x-1/2\r<BR>\n" );
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document.write( "*Note point slope form becomes very important in later math courses and is very helpeful for calculus so keep that in mind. </SPAN>\n" );
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