document.write( "Question 137252: A carpenter charges a set fee for each job in additon to his hourly charge. If a carpenter bills a customer $150 for a job which takes him 3 hours and bills a second customer $180 for a 6 hour job, how much would he charge for a job that takes him 9 hours? \n" ); document.write( "
Algebra.Com's Answer #100427 by KissedPeach(1)\"\" \"About 
You can put this solution on YOUR website!
Using the five step method your answer would be.\r
\n" ); document.write( "\n" ); document.write( "1. The problem asks for the amount charged for a 9 hour job.
\n" ); document.write( "2. let x= the set fee and let y= the hourly charge.
\n" ); document.write( "3 (150-3y) + 6y = 180
\n" ); document.write( "4 (150-3y)+6y=180
\n" ); document.write( " 150-150 -3y + 6y =180
\n" ); document.write( " -3y+6y = 30
\n" ); document.write( " 3y=30
\n" ); document.write( " y=10\r
\n" ); document.write( "\n" ); document.write( " x=150-(3*10)
\n" ); document.write( " x=150-30
\n" ); document.write( " x=120
\n" ); document.write( "
\n" ); document.write( " 120+(9*10)=x
\n" ); document.write( " 120+90=x
\n" ); document.write( " 210=x\r
\n" ); document.write( "\n" ); document.write( "5. 120+(3*10)=150
\n" ); document.write( " 120+30=150
\n" ); document.write( " 150=150\r
\n" ); document.write( "\n" ); document.write( " 120+(6*10)=180
\n" ); document.write( " 120+60=180
\n" ); document.write( " 180=180\r
\n" ); document.write( "\n" ); document.write( " 120+(9*10)=210
\n" ); document.write( " 120+10=210
\n" ); document.write( " 210=210\r
\n" ); document.write( "\n" ); document.write( " the carpenter charges $210 for a 9 hour job.
\n" ); document.write( "
\n" );