document.write( "Question 137252: A carpenter charges a set fee for each job in additon to his hourly charge. If a carpenter bills a customer $150 for a job which takes him 3 hours and bills a second customer $180 for a 6 hour job, how much would he charge for a job that takes him 9 hours? \n" ); document.write( "
Algebra.Com's Answer #100427 by KissedPeach(1)![]() ![]() ![]() You can put this solution on YOUR website! Using the five step method your answer would be.\r \n" ); document.write( "\n" ); document.write( "1. The problem asks for the amount charged for a 9 hour job. \n" ); document.write( "2. let x= the set fee and let y= the hourly charge. \n" ); document.write( "3 (150-3y) + 6y = 180 \n" ); document.write( "4 (150-3y)+6y=180 \n" ); document.write( " 150-150 -3y + 6y =180 \n" ); document.write( " -3y+6y = 30 \n" ); document.write( " 3y=30 \n" ); document.write( " y=10\r \n" ); document.write( "\n" ); document.write( " x=150-(3*10) \n" ); document.write( " x=150-30 \n" ); document.write( " x=120 \n" ); document.write( " \n" ); document.write( " 120+(9*10)=x \n" ); document.write( " 120+90=x \n" ); document.write( " 210=x\r \n" ); document.write( "\n" ); document.write( "5. 120+(3*10)=150 \n" ); document.write( " 120+30=150 \n" ); document.write( " 150=150\r \n" ); document.write( "\n" ); document.write( " 120+(6*10)=180 \n" ); document.write( " 120+60=180 \n" ); document.write( " 180=180\r \n" ); document.write( "\n" ); document.write( " 120+(9*10)=210 \n" ); document.write( " 120+10=210 \n" ); document.write( " 210=210\r \n" ); document.write( "\n" ); document.write( " the carpenter charges $210 for a 9 hour job. \n" ); document.write( " |