document.write( "Question 137247This question is from textbook
\n" ); document.write( ": Why is it true that at the x-intercept, the value of y is 0, and at the y-intercept, the value of x is 0? Please give 1 or 2 examples please?\r
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Algebra.Com's Answer #100416 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
The x-intercept is the point at which the line or curve crosses (intercepts) the x-axis, and, everywhere along the x-axis, the y-coordinate is zero (y = 0).
\n" ); document.write( "Similarly, the y-intercept is the point at which the line or curve crosses (intercepts) the y-axis, and, everywhere along the y-axis, the x-coordinate is zero (x = 0).
\n" ); document.write( "Example:
\n" ); document.write( "Graph the linear equation:
\n" ); document.write( "\"y+=+2x%2B4\" and identify the x-intercept and the y-intercept:
\n" ); document.write( "\"graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C2x%2B4%29\"
\n" ); document.write( "You can see from the graph that the x-intercept is (-2, 0) and the y-intercept is (0, 4). You'll notice that the y-coordinate and the x-coordinate, respectively, are zero in the two points.
\n" ); document.write( "You could have arrived at this conclusion algebraically:
\n" ); document.write( "For the y-intercept, set x = 0 and solve for y.
\n" ); document.write( "\"y+=+2x%2B4\" Set x = 0.
\n" ); document.write( "\"y+=+2%280%29%2B4\"
\n" ); document.write( "\"y+=+4\"The y-intercept is then (0, 4)
\n" ); document.write( "For the x-intercept, set y = 0 and solve for x.
\n" ); document.write( "\"y+=+2x%2B4\" Set y = 0.
\n" ); document.write( "\"0+=+2x%2B4\" Subtract 4 from both sides.
\n" ); document.write( "\"-4+=+2x\" Divide both sides b 2.
\n" ); document.write( "\"x+=+-2\" The x-intercept is then (-2, 0) \n" ); document.write( "
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