document.write( "Question 137109: John drove to a distant city in 5 hours, when he returned, there was less traffic, and the trip took only 3hrs. If John drove 26 mph faster on the return trip, how fast did he drive each way? \n" ); document.write( "
Algebra.Com's Answer #100393 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
5X=3(X+26)
\n" ); document.write( "5X=3X+78
\n" ); document.write( "5X-3X=78
\n" ); document.write( "2X=78
\n" ); document.write( "X=78/2
\n" ); document.write( "X=39 MPH FOR THE FIRST TRIP
\n" ); document.write( "39+26=65 MPH FOR THE RETURN TRIP
\n" ); document.write( "PROOF:
\n" ); document.write( "5*39=3*65
\n" ); document.write( "195=195 MILEAGE DRIVEN.
\n" ); document.write( "
\n" );