document.write( "Question 137138This question is from textbook College Algebra
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document.write( ": x-4Square root x+3=0
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document.write( "This is how far I got (x-4)=(Square root x+3) \n" );
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Algebra.Com's Answer #100344 by stanbon(75887) ![]() You can put this solution on YOUR website! x-4Square root x+3=0 \n" ); document.write( "x-4sqrt(x+3) = 0 \n" ); document.write( "x^2 = 16(x+3) \n" ); document.write( "x^2-16x-3 = 0 \n" ); document.write( "x=[16 +- sqrt(16^2-4*-3)]/2 \n" ); document.write( "x=[16 +- 16.3707...]/2 \n" ); document.write( "x= 16.1854 or x = -0.18545,, \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |