document.write( "Question 137138This question is from textbook College Algebra
\n" ); document.write( ": x-4Square root x+3=0
\n" ); document.write( "This is how far I got (x-4)=(Square root x+3)
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Algebra.Com's Answer #100344 by stanbon(75887)\"\" \"About 
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x-4Square root x+3=0
\n" ); document.write( "x-4sqrt(x+3) = 0
\n" ); document.write( "x^2 = 16(x+3)
\n" ); document.write( "x^2-16x-3 = 0
\n" ); document.write( "x=[16 +- sqrt(16^2-4*-3)]/2
\n" ); document.write( "x=[16 +- 16.3707...]/2
\n" ); document.write( "x= 16.1854 or x = -0.18545,,
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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