document.write( "Question 137147: 1/2 log base 8 (x+5) - 3 log base 8 y
\n" ); document.write( "this is what i have so far\r
\n" ); document.write( "\n" ); document.write( "=log base 8(x+5)^1/2-log base 8 y^3
\n" ); document.write( "=log base 8 x^1/2 + 5^1/2-log base 8 y^3\r
\n" ); document.write( "\n" ); document.write( "now I'm stumped. If some one could help I would greatly appreciate it. \r
\n" ); document.write( "\n" ); document.write( "THanks so much.
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Algebra.Com's Answer #100340 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1/2 log base 8 (x+5) - 3 log base 8 y
\n" ); document.write( "this is what i have so far
\n" ); document.write( "=log base 8(x+5)^1/2-log base 8 y^3
\n" ); document.write( "=log base 8 x^1/2 + 5^1/2-log base 8 y^3
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "1/2 log (base 8) (x+5) - 3 log (base 8) y\r
\n" ); document.write( "\n" ); document.write( "= log8 (x+5)^1/2 - log8 y^3\r
\n" ); document.write( "\n" ); document.write( "= log8 [(sqrt(x+5))/y^3]
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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