document.write( "Question 137128: How do I compute the x and y axis intercepts of a quadratic function? Please provide an example to illustrate the explanation. Thank you \n" ); document.write( "

Algebra.Com's Answer #100332 by oscargut(2103) $\"\"$ $\"About$

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if f(x)=ax^2+bx+c
\n" ); document.write( "then
\n" ); document.write( " y axis intercept is P=(0,f(0))=(0,c)
\n" ); document.write( "x axis intercept are the roots of f(x)
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "f(x)=x^2-5x+6
\n" ); document.write( "y axis intercept is P=(0,6)
\n" ); document.write( " $\"x+=+%285+%2B-+sqrt%28+25-4%2A1%2A6+%29%29%2F%282%2A1%29+\"$
\n" ); document.write( "x axis intercept are x=2 and x=3
\n" ); document.write( "point are (2,0) and (3,0)
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