document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=137036>Question 137036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the area of a Pentagon with the side lenths of 2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #100316 by </B><A HREF=/tutors/aboutme.mpl?userid=jedidiah><B>jedidiah(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jedidiah><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=100316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area of triangle (1/5 area of polygon) = (1/2)bh<BR>\n" );
document.write( "b=2<BR>\n" );
document.write( "angle of each vertex:<BR>\n" );
document.write( "(5-2)(180 degrees)/5 vertices = 108 degrees\r<BR>\n" );
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document.write( "angle of triangle opposite h:<BR>\n" );
document.write( "108/2 = 54 degrees\r<BR>\n" );
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document.write( "height of triangle:<BR>\n" );
document.write( "h= 1*tan(54 degrees)= 1.38\r<BR>\n" );
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document.write( "area of triangle= (1/2)*2*1.38= 1.38\r<BR>\n" );
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document.write( "area of pentagon:<BR>\n" );
document.write( "5*1.38= 6.9 units^2 </SPAN>\n" );
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