document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20791>Question 20791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two thirds of a number reduced by 11 is equal to 4 more than the number. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10031 by </B><A HREF=/tutors/aboutme.mpl?userid=kapilsinghi><B>kapilsinghi(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kapilsinghi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number  = x<BR>\n" );
document.write( "(2/3)*x - 11 = x + 4\r<BR>\n" );
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document.write( "2x/3 - 11 = x + 4\r<BR>\n" );
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document.write( "2x/3 = x + 15\r<BR>\n" );
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document.write( "2x = 3x + 45\r<BR>\n" );
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document.write( "x = -45\r<BR>\n" );
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