document.write( "Question 137064: ln (x + 6) - ln 10 = ln(x-1) - ln 2\r
\n" ); document.write( "\n" ); document.write( "Can you please show me the steps on how to solve this problem along with one like...\r
\n" ); document.write( "\n" ); document.write( "log 3x - 2[logx - log(2+y)] \n" ); document.write( "
Algebra.Com's Answer #100297 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
ln (x + 6) - ln 10 = ln(x-1) - ln 2 \r
\n" ); document.write( "\n" ); document.write( "ln[(x+6)/10] = ln[(x-1)/2]
\n" ); document.write( "(x+6)/10 = (x-1)/2
\n" ); document.write( "Cross multiply to get:
\n" ); document.write( "2x+12 = 10x-10
\n" ); document.write( "8x = 22
\n" ); document.write( "x = 11/4
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\n" ); document.write( "\n" ); document.write( "Can you please show me the steps on how to solve this problem along with one like...
\n" ); document.write( "log 3x - 2[logx - log(2+y)]\r
\n" ); document.write( "\n" ); document.write( "Comment: You can't solve this one because it is not an equation:\r
\n" ); document.write( "\n" ); document.write( "log3x -2logx + 2log(2+y)\r
\n" ); document.write( "\n" ); document.write( "= log[(3x*2+y)/x^2]\r
\n" ); document.write( "\n" ); document.write( "=========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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