document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=137047>Question 137047</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395937760/algebrahomeworkh>McDougal Littell's Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Usually I know how to factor up to four terms (by grouping method), but this particular problem caught me because it is five terms. Here is the problem: Factor the expression completely: 7n^5+7n^4-3n^2-6n-3. Please explain it, and help! Thank you so much. :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #100294 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=100294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(n) = 7n^5+7n^4-3n^2-6n-3<BR>\n" );
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document.write( "= 7n^4(n+1) -3(n^2+2n+1)\r<BR>\n" );
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document.write( "= 7n^4(n+1) -3(n+1)^2\r<BR>\n" );
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document.write( "= (n+1)[7n^4 -3(n+1)]\r<BR>\n" );
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document.write( "= (n+1)[7n^4-3n-3]<BR>\n" );
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document.write( "Comment: 7n^4 -3n -3 is not factorable in the Real Number system.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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