document.write( "Question 137004: I would appreciate it if anyone could help me understand how to solve the problem I've typed out and also the solution..thanx!\r
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\n" ); document.write( "\n" ); document.write( "A certain number is expressed by three digits whose sum is 10. The sum of the first and last digits is two-thirds(2/3) of the second digit, and if 198 is subtracted from the number, the digits will be reversed. What is the number?
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Algebra.Com's Answer #100280 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
let h=\"hundreds digit\", t=\"tens digit\", and u=\"units digit\"\r
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\n" ); document.write( "\n" ); document.write( "\"three digits whose sum is 10\" __ h+t+u=10
\n" ); document.write( "__ multiplying by 3 __ 3h+3t+3u=30\r
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\n" ); document.write( "\n" ); document.write( "\"sum of the first and last digits is two-thirds(2/3) of the second digit\" __ h+u={2/3)t
\n" ); document.write( "__ multiplying by 3 __ 3h+3u=2t\r
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\n" ); document.write( "\n" ); document.write( "substituting __ 3t+2t=30 __ 5t=30 __ t=6
\n" ); document.write( "__ substituting __ h+6+u=10 __ h=4-u\r
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\n" ); document.write( "\n" ); document.write( "\"if 198 is subtracted from the number, the digits will be reversed\" __ 100h+10t+u-198=100u+10t+h
\n" ); document.write( "__ subtracting 10t __ 100h+u-198=100u+h\r
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\n" ); document.write( "\n" ); document.write( "substituting __ 100(4-u)+u-198=100u+4-u __ 400-100u+u-198=99u+4 __ 198=198u __ 1=u
\n" ); document.write( "__ substituting __ h=4-1 __ h=3\r
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\n" ); document.write( "\n" ); document.write( "361 is the number
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