document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136879>Question 136879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the distance between (6,-1)and (-3,7)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #100270 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=100270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance between (6,-1)and (-3,7)is:<BR>\n" );
document.write( "for the x distance we have 6+3=9<BR>\n" );
document.write( "for the y distance we have 7+1=8<BR>\n" );
document.write( "thus we have a right triangle with 2 sides of 9 & 8 & we're looking for the hypotenuse using:<BR>\n" );
document.write( "[a^2+b^2=c^2].<BR>\n" );
document.write( "8^2+9^2=h^2<BR>\n" );
document.write( "64+81=h^2<BR>\n" );
document.write( "145=h^2<BR>\n" );
document.write( "h=sqrt145<BR>\n" );
document.write( "h=12.0416 is the distance between these 2 points. </SPAN>\n" );
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