document.write( "Question 136996: Using the given equations of parabolas, find the focus, the directrix and the equation of the axis of symmetry.\r
\n" ); document.write( "\n" ); document.write( "y=1/20 x^2
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Algebra.Com's Answer #100269 by solver91311(24713)\"\" \"About 
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The equation of a parabola with vertex (h,k), axis of symmetry parallel to the y-axis, opening upwards, and distance from the vertex to the directrix of a is:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2=4a%28y-k%29\"\r
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\n" ); document.write( "\n" ); document.write( "Rearranging your equation:\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F20%29+x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=20y\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-0%29%5E2=4%285%29%28y-0%29\"\r
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\n" ); document.write( "\n" ); document.write( "So you can see that \"h+=+0\", \"k+=+0\", and \"a=5\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore the vertex is (0,0). The axis of symmetry, known to be parallel to the y-axis, passes through the vertex, therefore the axis of symmetry is the y-axis, or \"x=0\".\r
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\n" ); document.write( "\n" ); document.write( "The directrix is a line perpendicular to the axis of symmetry, a units distant from the vertex. Since the axis of symmetry is a vertical line, the directrix is a horizontal line. 5 units below the vertex on the y-axis is the point (0,-5) and the directrix is the horizontal line intersecting this point, or \"y=-5\".\r
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\n" ); document.write( "\n" ); document.write( "The focus is a point on the axis of symmetry a units from the vertex, since the point is on the axis of symmetry, \"x=0\", the x-coordinate of the focus must be 0. Since the focus is \"a=5\" units from the vertex, the y-coordinate of the focus must be 5. Therefore the focus is at (0,5)
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