document.write( "Question 136996: Using the given equations of parabolas, find the focus, the directrix and the equation of the axis of symmetry.\r
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document.write( "y=1/20 x^2 \n" );
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Algebra.Com's Answer #100269 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! The equation of a parabola with vertex (h,k), axis of symmetry parallel to the y-axis, opening upwards, and distance from the vertex to the directrix of a is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rearranging your equation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So you can see that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore the vertex is (0,0). The axis of symmetry, known to be parallel to the y-axis, passes through the vertex, therefore the axis of symmetry is the y-axis, or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The directrix is a line perpendicular to the axis of symmetry, a units distant from the vertex. Since the axis of symmetry is a vertical line, the directrix is a horizontal line. 5 units below the vertex on the y-axis is the point (0,-5) and the directrix is the horizontal line intersecting this point, or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The focus is a point on the axis of symmetry a units from the vertex, since the point is on the axis of symmetry, |