document.write( "Question 136751: Q1. Rearrange x = 1/2 A In (q - 3) + c to obtain q\r
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\n" ); document.write( "\n" ); document.write( "Q2. Make y the subject E = P (1 - e^(y - 1)) \n" ); document.write( "
Algebra.Com's Answer #100267 by ankor@dixie-net.com(22740)\"\" \"About 
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Q1. Rearrange x = 1/2 A In (q - 3) + c to obtain q
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\n" ); document.write( "Multiply equation by 2 to get rid of the denominator
\n" ); document.write( "2x = A*ln(q-3) + 2c
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\n" ); document.write( "Subtract 2c from both sides:
\n" ); document.write( "2x - 2c = A*ln(q-3)
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\n" ); document.write( "Divide both sides by A
\n" ); document.write( "\"%28%282x-2c%29%29%2FA\" = ln(q-3)
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\n" ); document.write( "Use the exponent equivalent of logs
\n" ); document.write( "\"e%5E%28%28%282x-2c%29%2FA%29%29\" = q - 3; Note that\"%28%282x-2c%29%29%2FA\" is the exponent of e
\n" ); document.write( "Add 3 to both sides
\n" ); document.write( "q = \"e%5E%28%28%282x-2c%29%2FA%29%29%2B3\"
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\n" ); document.write( "Q2. Make y the subject E = P (1 - e^(y - 1))
\n" ); document.write( "Divide both sides by P
\n" ); document.write( "\"E%2FP\" = \"1-e%5E%28%28y-1%29%29\"
\n" ); document.write( "or we can arrange it:
\n" ); document.write( "\"e%5E%28%28y-1%29%29\" = 1 - \"E%2FP\"
\n" ); document.write( "Find the natural log of both sides(ln of e is 1)
\n" ); document.write( "y - 1 = \"ln%281-%28E%2FP%29%29\"
\n" ); document.write( "Add 1 to both sides:
\n" ); document.write( "y = \"ln%281-%28E%2FP%29%29\" +1 \n" ); document.write( "
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