document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136981>Question 136981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i dont understand this problem at all! please help me! log7(bottom of the g)49=x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #100259 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=100259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> from your description, the assumption is that the 7 is a subscript that indicates the base of the logarithm\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "translating from logs to exponents __ 7^x=49\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x is the power that 7 is raised to, to get 49 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );