document.write( "Question 136962: How many liters of a 60% alcohol solution must be mixed with 90 liters of a 90% solution to get a 80% solution \n" ); document.write( "
Algebra.Com's Answer #100255 by checkley77(12844)\"\" \"About 
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.6X+.9*90=.8(90+X)
\n" ); document.write( ".6X+81=72+.8X
\n" ); document.write( ".6X-.8X=72-81
\n" ); document.write( "-.2X=-9
\n" ); document.write( "X=-9/-.2
\n" ); document.write( "X=45 LITERS OF 60% ALCOHOL IS NEEDED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".6*45+.9*90=.8(90+45)
\n" ); document.write( "27+81=.8(135)
\n" ); document.write( "108=108
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