document.write( "Question 136962: How many liters of a 60% alcohol solution must be mixed with 90 liters of a 90% solution to get a 80% solution \n" ); document.write( "
Algebra.Com's Answer #100255 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .6X+.9*90=.8(90+X) \n" ); document.write( ".6X+81=72+.8X \n" ); document.write( ".6X-.8X=72-81 \n" ); document.write( "-.2X=-9 \n" ); document.write( "X=-9/-.2 \n" ); document.write( "X=45 LITERS OF 60% ALCOHOL IS NEEDED. \n" ); document.write( "PROOF: \n" ); document.write( ".6*45+.9*90=.8(90+45) \n" ); document.write( "27+81=.8(135) \n" ); document.write( "108=108 \n" ); document.write( " \n" ); document.write( " |