document.write( "Question 136945This question is from textbook Intermediate Algebra
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document.write( ": The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round your answer to the nearest pound of force? \n" );
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Algebra.Com's Answer #100222 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. \n" ); document.write( "--- \n" ); document.write( "F = k*w*s^2/r \n" ); document.write( "------------------- \n" ); document.write( " If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet \n" ); document.write( "--- \n" ); document.write( "3600 = k*1800*20^2/600 \n" ); document.write( "k = 3 \n" ); document.write( "--------- \n" ); document.write( "Equation for your problem: \n" ); document.write( "F = 3*w*s^2/r \n" ); document.write( "-------- \n" ); document.write( " what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round your answer to the nearest pound of force? \n" ); document.write( "--------------------- \n" ); document.write( "F = 3*1800*50^2/570 \n" ); document.write( "F = 23684.21 lbs. of force \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |